4.9x=0.01x^2

Solution for 4.9x=0.01x^2 equation:

4.9x=0.01x^2

We move all terms to the left:

4.9x-(0.01x^2)=0

We get rid of parentheses

-0.01x^2+4.9x=0

a = -0.01; b = 4.9; c = 0;
Δ = b2-4ac
Δ = 4.92-4·(-0.01)·0
Δ = 24.01
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4.9)-\sqrt{24.01}}{2*-0.01}=\frac{-4.9-\sqrt{24.01}}{-0.02}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4.9)+\sqrt{24.01}}{2*-0.01}=\frac{-4.9+\sqrt{24.01}}{-0.02}
$